Optimal. Leaf size=139 \[ \frac {2203}{320} \sqrt {1-2 x} (2+3 x)^2 \sqrt {3+5 x}+\frac {27}{16} \sqrt {1-2 x} (2+3 x)^3 \sqrt {3+5 x}+\frac {(2+3 x)^4 \sqrt {3+5 x}}{\sqrt {1-2 x}}+\frac {\sqrt {1-2 x} \sqrt {3+5 x} (11129753+4618500 x)}{51200}-\frac {92108287 \sin ^{-1}\left (\sqrt {\frac {2}{11}} \sqrt {3+5 x}\right )}{51200 \sqrt {10}} \]
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Rubi [A]
time = 0.02, antiderivative size = 139, normalized size of antiderivative = 1.00, number of steps
used = 6, number of rules used = 5, integrand size = 26, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.192, Rules used = {99, 158, 152,
56, 222} \begin {gather*} -\frac {92108287 \text {ArcSin}\left (\sqrt {\frac {2}{11}} \sqrt {5 x+3}\right )}{51200 \sqrt {10}}+\frac {\sqrt {5 x+3} (3 x+2)^4}{\sqrt {1-2 x}}+\frac {27}{16} \sqrt {1-2 x} \sqrt {5 x+3} (3 x+2)^3+\frac {2203}{320} \sqrt {1-2 x} \sqrt {5 x+3} (3 x+2)^2+\frac {\sqrt {1-2 x} \sqrt {5 x+3} (4618500 x+11129753)}{51200} \end {gather*}
Antiderivative was successfully verified.
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Rule 56
Rule 99
Rule 152
Rule 158
Rule 222
Rubi steps
\begin {align*} \int \frac {(2+3 x)^4 \sqrt {3+5 x}}{(1-2 x)^{3/2}} \, dx &=\frac {(2+3 x)^4 \sqrt {3+5 x}}{\sqrt {1-2 x}}-\int \frac {(2+3 x)^3 \left (41+\frac {135 x}{2}\right )}{\sqrt {1-2 x} \sqrt {3+5 x}} \, dx\\ &=\frac {27}{16} \sqrt {1-2 x} (2+3 x)^3 \sqrt {3+5 x}+\frac {(2+3 x)^4 \sqrt {3+5 x}}{\sqrt {1-2 x}}+\frac {1}{40} \int \frac {\left (-5035-\frac {33045 x}{4}\right ) (2+3 x)^2}{\sqrt {1-2 x} \sqrt {3+5 x}} \, dx\\ &=\frac {2203}{320} \sqrt {1-2 x} (2+3 x)^2 \sqrt {3+5 x}+\frac {27}{16} \sqrt {1-2 x} (2+3 x)^3 \sqrt {3+5 x}+\frac {(2+3 x)^4 \sqrt {3+5 x}}{\sqrt {1-2 x}}-\frac {\int \frac {(2+3 x) \left (\frac {1770165}{4}+\frac {5773125 x}{8}\right )}{\sqrt {1-2 x} \sqrt {3+5 x}} \, dx}{1200}\\ &=\frac {2203}{320} \sqrt {1-2 x} (2+3 x)^2 \sqrt {3+5 x}+\frac {27}{16} \sqrt {1-2 x} (2+3 x)^3 \sqrt {3+5 x}+\frac {(2+3 x)^4 \sqrt {3+5 x}}{\sqrt {1-2 x}}+\frac {\sqrt {1-2 x} \sqrt {3+5 x} (11129753+4618500 x)}{51200}-\frac {92108287 \int \frac {1}{\sqrt {1-2 x} \sqrt {3+5 x}} \, dx}{102400}\\ &=\frac {2203}{320} \sqrt {1-2 x} (2+3 x)^2 \sqrt {3+5 x}+\frac {27}{16} \sqrt {1-2 x} (2+3 x)^3 \sqrt {3+5 x}+\frac {(2+3 x)^4 \sqrt {3+5 x}}{\sqrt {1-2 x}}+\frac {\sqrt {1-2 x} \sqrt {3+5 x} (11129753+4618500 x)}{51200}-\frac {92108287 \text {Subst}\left (\int \frac {1}{\sqrt {11-2 x^2}} \, dx,x,\sqrt {3+5 x}\right )}{51200 \sqrt {5}}\\ &=\frac {2203}{320} \sqrt {1-2 x} (2+3 x)^2 \sqrt {3+5 x}+\frac {27}{16} \sqrt {1-2 x} (2+3 x)^3 \sqrt {3+5 x}+\frac {(2+3 x)^4 \sqrt {3+5 x}}{\sqrt {1-2 x}}+\frac {\sqrt {1-2 x} \sqrt {3+5 x} (11129753+4618500 x)}{51200}-\frac {92108287 \sin ^{-1}\left (\sqrt {\frac {2}{11}} \sqrt {3+5 x}\right )}{51200 \sqrt {10}}\\ \end {align*}
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Mathematica [A]
time = 0.18, size = 78, normalized size = 0.56 \begin {gather*} \frac {-10 \sqrt {3+5 x} \left (-14050073+9587886 x+5020200 x^2+2283840 x^3+518400 x^4\right )+92108287 \sqrt {10-20 x} \tan ^{-1}\left (\frac {\sqrt {\frac {5}{2}-5 x}}{\sqrt {3+5 x}}\right )}{512000 \sqrt {1-2 x}} \end {gather*}
Antiderivative was successfully verified.
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Maple [A]
time = 0.08, size = 140, normalized size = 1.01
method | result | size |
default | \(-\frac {\left (-10368000 x^{4} \sqrt {-10 x^{2}-x +3}-45676800 x^{3} \sqrt {-10 x^{2}-x +3}+184216574 \sqrt {10}\, \arcsin \left (\frac {20 x}{11}+\frac {1}{11}\right ) x -100404000 x^{2} \sqrt {-10 x^{2}-x +3}-92108287 \sqrt {10}\, \arcsin \left (\frac {20 x}{11}+\frac {1}{11}\right )-191757720 x \sqrt {-10 x^{2}-x +3}+281001460 \sqrt {-10 x^{2}-x +3}\right ) \sqrt {1-2 x}\, \sqrt {3+5 x}}{1024000 \left (-1+2 x \right ) \sqrt {-10 x^{2}-x +3}}\) | \(140\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A]
time = 0.53, size = 94, normalized size = 0.68 \begin {gather*} -\frac {81}{160} \, {\left (-10 \, x^{2} - x + 3\right )}^{\frac {3}{2}} x - \frac {92108287}{1024000} \, \sqrt {5} \sqrt {2} \arcsin \left (\frac {20}{11} \, x + \frac {1}{11}\right ) - \frac {1557}{640} \, {\left (-10 \, x^{2} - x + 3\right )}^{\frac {3}{2}} + \frac {154953}{2560} \, \sqrt {-10 \, x^{2} - x + 3} x + \frac {6740553}{51200} \, \sqrt {-10 \, x^{2} - x + 3} - \frac {2401 \, \sqrt {-10 \, x^{2} - x + 3}}{16 \, {\left (2 \, x - 1\right )}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A]
time = 0.50, size = 91, normalized size = 0.65 \begin {gather*} \frac {92108287 \, \sqrt {10} {\left (2 \, x - 1\right )} \arctan \left (\frac {\sqrt {10} {\left (20 \, x + 1\right )} \sqrt {5 \, x + 3} \sqrt {-2 \, x + 1}}{20 \, {\left (10 \, x^{2} + x - 3\right )}}\right ) + 20 \, {\left (518400 \, x^{4} + 2283840 \, x^{3} + 5020200 \, x^{2} + 9587886 \, x - 14050073\right )} \sqrt {5 \, x + 3} \sqrt {-2 \, x + 1}}{1024000 \, {\left (2 \, x - 1\right )}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {\left (3 x + 2\right )^{4} \sqrt {5 x + 3}}{\left (1 - 2 x\right )^{\frac {3}{2}}}\, dx \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A]
time = 0.62, size = 97, normalized size = 0.70 \begin {gather*} -\frac {92108287}{512000} \, \sqrt {10} \arcsin \left (\frac {1}{11} \, \sqrt {22} \sqrt {5 \, x + 3}\right ) + \frac {{\left (6 \, {\left (12 \, {\left (8 \, {\left (36 \, \sqrt {5} {\left (5 \, x + 3\right )} + 361 \, \sqrt {5}\right )} {\left (5 \, x + 3\right )} + 28181 \, \sqrt {5}\right )} {\left (5 \, x + 3\right )} + 4651913 \, \sqrt {5}\right )} {\left (5 \, x + 3\right )} - 460541435 \, \sqrt {5}\right )} \sqrt {5 \, x + 3} \sqrt {-10 \, x + 5}}{6400000 \, {\left (2 \, x - 1\right )}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [F]
time = 0.00, size = -1, normalized size = -0.01 \begin {gather*} \int \frac {{\left (3\,x+2\right )}^4\,\sqrt {5\,x+3}}{{\left (1-2\,x\right )}^{3/2}} \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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